-8x+0.25x^2=-48

Solution for -8x+0.25x^2=-48 equation:

-8x+0.25x^2=-48

We move all terms to the left:

-8x+0.25x^2-(-48)=0

We add all the numbers together, and all the variables

0.25x^2-8x+48=0

a = 0.25; b = -8; c = +48;
Δ = b2-4ac
Δ = -82-4·0.25·48
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4}{2*0.25}=\frac{4}{0.5}
=8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4}{2*0.25}=\frac{12}{0.5}
=24
$